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28x^2-63x+35=0
a = 28; b = -63; c = +35;
Δ = b2-4ac
Δ = -632-4·28·35
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-7}{2*28}=\frac{56}{56} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+7}{2*28}=\frac{70}{56} =1+1/4 $
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